BITSAT Iteration 2 Seat Allotment Results 2024 Out Now

bits of x and y are l's Let the result of the division be z = Zn - 12n − 2 · · Z120 The n bits of z are computed in n iterations ( In fact an

1st- Iteration · Firstly, BITS doesn't release iteration wise cutoffs, · Based on the data of 490 students posted iin the BITSAT

bits iteration 2 BITSAT Iteration 2 Result 2024: To get the results of the second round of seat allocation for BITSAT 2024, candidates will require their login

bits slot booking phase 2 2 10 -1 1 B E R System 2 SP L=16, GM D int =180,000 bits 0 iterations 1 iteration 2 iterations 3 iterations 7 iterations 20 iterations 50 iterations 100